A solid conducting sphere of radius a
Non-conducting supports are used to maintain this configuration of spheres. Take electric potential to be zero at infinity. Skip to main content. Table of contents.
Use app Login. A solid conducting sphere of radius a having a charge q is surrounded by a concentric conducting spherical shell of inner radius 2a and outer radius 3a as shown in figure. Open in App. Verified by Toppr. Similar Questions. A solid conducting sphere of radius a having a charge q is surrounded by a concentric conducting spherical shell of inner radius 2 a and outer radius 3 a as shown in figure. View Solution.
A solid conducting sphere of radius a
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It turns out that in situations that have certain symmetries spherical, cylindrical, or planar in the charge distribution, we can deduce the electric field based on knowledge of the electric flux. In these systems, we can find a Gaussian surface S over which the electric field has constant magnitude. Note that these symmetries lead to the transformation of the flux integral into a product of the magnitude of the electric field and an appropriate area. The direction of the electric field at point P is obtained from the symmetry of the charge distribution and the type of charge in the distribution. Here is a summary of the steps we will follow:. They are. To exploit the symmetry, we perform the calculations in appropriate coordinate systems and use the right kind of Gaussian surface for that symmetry, applying the remaining four steps. A charge distribution has spherical symmetry if the density of charge depends only on the distance from a point in space and not on the direction. Thus, it is not the shape of the object but rather the shape of the charge distribution that determines whether or not a system has spherical symmetry.
A solid conducting sphere of radius a
Imagine for a moment that we have two neutrally-charged but otherwise arbitrary conductors, separated in space. Figure 2. Clearly there is an electric field pointing out of the former, and into the latter, with the field lines leaving and landing perpendicular to the surfaces. That is, the positively-charged conductor will be an equipotential at a higher voltage than the equipotential that is the negatively-charged conductor. What would we expect to see change in the electric field? We would expect the magnitude of the electric field to change, but the field lines should be shaped exactly the same.
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Question 2 Hard. Publisher: OpenStax. D None of the above. Montgomery Questions. Knowledge Booster. A conducting spherical shell having inner radius a and outer radius b carries a net charge Q. Briefly describe why astronauts are weightless in th Electric Flux. Cancel Send Feedback. Rooms A and B are the same size, and are connected by an open door. Kepler's Third Law. Notes Access past notes and exams matches to your classes Study Groups Study with your friends by joining virtual study sessions Free Unlocks Download the mobile app and receive 3 free video solutions. The nuclei of large atoms, such as uranium, with 92 protons, can be Equilibrium in 2D. If the same charge Q were distributed uniformly throughout a sphere of radius 2R, the magnitude of the electric field at the same distance r1 from the center would be equal to a E.
The electric field of a point charge Q can be obtained by a straightforward application of Gauss' law. Considering a Gaussian surface in the form of a sphere at radius r , the electric field has the same magnitude at every point of the sphere and is directed outward. The electric flux is then just the electric field times the area of the sphere.
Adding Mass to a Moving System. Text Solution. An electric dipole is placed in a uniform electric field vec E of ma Schedule classes. High dosage tutoring from Dedicated 3 experts. Moment of Inertia via Integration. If a point charge q is placed at the centre of this shell, then the surface charge density on the outer surface of the shell is given as:. Angular Momentum of a Point Mass. Reflection of Light. Topic: Optics. Take electric potential to be zero at infinity. Problem Using Thomsons outdated model of he atom described in Magnets and Magnetic Fields.
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